Suppose that P( x 1, y 1) and Q( x 2, y 2)are two points and let M( x, y) be the midpoint. We can find a formula for the midpoint of any interval. Thus the coordinates of the midpoint M are (3, 5). The y coordinate of M is the average of 2 and 8. Hence the x-coordinate of M is the average of 1 and 5. Triangles AMS and MBT are congruent triangles (AAS), and so AS = MT and MS = BT. When the interval is not parallel to one of the axes we take the average of the x-coordinate and the y-coordinate. Note: 4 is the average of 1 and 7, that is, 4 =. Midpoint is at (4, 2), since 4 is halfway Note that ( x 2 − x 1) 2 is the same as ( x 1 − x 1) 2 and therefore it doesn’t matter whether we go from P to Q or from Q to P − the result is the same.įind the coordinates of the midpoint of the line interval AB, given:Ī A(1, 2) and B(7, 2) b A(1, −2) and B(1, 3) PX = x 2 − x 1 or x 1 − x 2 and QX = y 2 − y 1 or y 1 − y 2 Suppose that P( x 1, y 1) and Q( x 2, y 2) are two points.įorm the right-angled triangle PQX, where X is the point ( x 2, y 1), We can obtain a formula for the length of any interval. The distance between the points A(1, 2) and B(4, 6) is calculated below. Pythagoras’ theorem is used to calculate the distance between two points when the line interval between them is neither vertical nor horizontal. The example above considered the special cases when the line interval AB is either horizontal or vertical. The difference of the y-coordinates of the Find the distance between the following pairs of points.Ī A(1, 2) and B(4, 2) b A(1, −2) and B(1, 3)
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |